I would like to know how to order to PhoneGap to open ANY EXISTING LINK in the system web browser.
This is not working: < preference name="stay-in-webview" value="false" />
Solutions like
navigator.app.loadUrl('http://www.google.com', { openExternal:true } );
or
window.open('http://www.myurl.nl', '_blank', 'location=yes');
are no aceptable, because there are are some times that you fetch data from an api and there in the text exists links and you can not controlo or modify the content
Thant you very much
This is not working: < preference name="stay-in-webview" value="false" />
Solutions like
navigator.app.loadUrl('http://www.google.com', { openExternal:true } );
or
window.open('http://www.myurl.nl', '_blank', 'location=yes');
are no aceptable, because there are are some times that you fetch data from an api and there in the text exists links and you can not controlo or modify the content
Thant you very much

